How to Calculate Dyeing Recipe in Textile Wet Processing Sector?
Dyeing Recipe Calculation:
Dyeing recipe calculation is not a tough task that we have normally seemed. The person who is engaged in textile dyeing industry has to know the dyeing recipe calculation method to dye the fabric perfectly. This article has presented an easy method for calculating dyeing recipe calculation in textile wet processing sector.
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| Dyeing lab in textile |
Lab Dip Calculation Method Followed in Textile Dyeing Industry:
The below equipment’s has needed to calculate the dyeing recipe in textile wet processingindustry.
- Digital weighting meter with glass box (Explorer, USA),
- Digital pipette,
- Microprocessor pH meter.
Dyeing Recipe Calculation Formula:
The below formulas have needed to calculate lab dip in textile dyeing industry.
1. Amount of dye calculation formula:
Required amount of dye,
(Weight of the fabric in gram × Shade percentage
=………………………………………………………………
Percentage of Stock solution
Or,
Required amount of solution,
Fw × Sp
=……………………
Cs
Where,
Fw indicates the weight of yarn, or fiber or fabric.
Sp indicates the shade percentage,
Cs indicates the concentration of stock solution.
2. Auxiliaries or Chemicals Calculation Formula:
The below formula has to follow to calculate required amount of auxiliaries or chemicals.
Required amount of solution (mls),
(Weight of substrate x Gram per liquor required x Liquor ratio)
=………..……………………………………………………………………
(Concentration percentage of stock solution× 10)
3. Additional Auxiliaries Calculation Formula:
Formula for addition of auxiliaries in solids form such as salt, soda is:
Salt in gram per liquor,
Sample weight x Liquor Ratio× required amount (%)
=………………………………………………………………………
1000
4. Percentage to Gram Conversion Calculation Formula:
Conversion formula from percentage to gram/ liquor is in the below:
Gram per liquor,
= Required amount in percentage x 10
If alkali concentration is given then the below formula has to follow for calculating this in gram per liquor:
Required amount of solution (mls),
(Weight of substrate x Gram per liquor required x Liquor ratio)
=……………………………………………………………………………….
(10 x Concentration percentage of stock solution)
Or,
Required amount of solution (mls),
Weight of substrate x Liquor ratio× required amount (%)
= ……………………………………………………………………….
Concentration percentage of stock solution
Lab Deep Calculation Example:
Recipe:
Dyes:
- Rema Blue RR = 1.122%
- React Red KHW = 2.014%
- React Yellow KHW = 1.486%
Chemicals:
Soda Ash (concentration.20%) = 5 gram/liter
Sample Weight. = 5 gram
Caustic Soda = 1.32%
Salt = 70%
Stock Solution (%) = 1
M: L = 1:8
Now, calculate the required recipe for dyes and auxiliaries or chemicals in gram per liter.
Solution:
In case of dyes,
We know,
Required amount of dye,
(Weight of the fabric in gram × Shade percentage
=……………………………………………………………………
Percentage of Stock solution
Calculation of dyestuff will be,
For,
- Rema Blue RR = (1.12 2x 5)/1=5.61 g/l
- React Yellow KHW = (1.486 x 5)/1= 7.43 g/l,
- React Red KHW = (2.014 x 5)/1= 10.07 g/l
In case of auxiliaries or chemicals,
We know,
Salt in gram per liquor,
Sample weight x Liquor Ratio× required amount (%)
=……………………………………………………………………
1000
5×8×70
=……………………….
1000
= 2.8gm
So, required amount of salt is 2.8gm
In case of Soda Ash (Concentration 20%):
Required amount of solution (mls),
(Weight of substrate x Gram per liquor required x Liquor ratio)
=……………………………………………………………………………………….
(10 x Concentration percentage of stock solution)
5×5×8
=……………………
10×20
= 1ml
So, required quantity of soda ash in c.c stands at 1.0
Extra Amount of Water Required:
= M: L – (Required amount of water to make solution of auxiliaries and dyes)
= [(5 x 8) – {(5.61+10.07+7.43) + (1.0+0.12)}]
= 40 – 24.112
= 15.77
So, 15.77 amount of salt is added in solid form
